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2 years ago

The length of a mathematical text book the is approximately 18.34cm and its width is 11.75 calculate ?

Mathematics

1 answer:

Aneli [31]2 years ago

4 0

Answer:

Perimeter=60.18cm

Area=215.495cm^2

Step-by-step explanation:

Given:

Length of book=18.34cm

Breadth=11.75cm

Solution:

Perimeter=2(l +b)

P=2(18.34+11.75)

P=2 x 30.09

P=60.18cm

Area=l x b

A=18.34 x 11.75

A=215.495 cm^2

Thank you!

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We are given that the length of the program was based on the assumption that the population mean time a shopper stands in a supermarket checkout line is 8 minutes.

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Let $\mu$ = actual mean waiting time.

(a) So, Null Hypothesis, $H_0$ : $\mu$ = 8 minutes {means that the actual mean waiting time does not differs from the standard}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 8 minutes {means that the actual mean waiting time differs from the standard}

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where, $\bar X$ = sample mean waiting time = 8.5 minutes

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So, test statistics = $\frac{8.5-8}{\frac{3.2}{\sqrt{120} } }$

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where, $\bar X$ = sample mean waiting time = 8.5 minutes

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Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population proportion, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

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95% confidence interval for $\mu$ = [ $\bar X-1.96 \times{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times{\frac{\sigma}{\sqrt{n} } }$ ]

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Therefore, 95% confidence interval for the population mean is [7.93 minutes , 9.07 minutes].

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The length of a mathematical text book the is approximately 18.34cm and its width is 11.75 calculate ?​

The length of a mathematical text book the is approximately 18.34cm and its width is 11.75 calculate ?