A dog runs from point O to B. The dog reaches A at 2.3 s into the sprint. Then the dog reaches C at 4.1 s. What is the average v
elocity of the dog from A to C?
will give brainliest
1 answer:
We are given
A dog runs from point O to B
t(OA)=2.3 s
t(OC)=4.1 s
now, we can find time between A and C
t(AC)=t(OC)-t(OA)
t(AC)=4.1-2.3
t(AC)=1.8 s
we are given
distance between A and C is 4m
so,
d=4m
now, we can find average velocity between A and C
we can plug values
so, option-C..................Answer
You might be interested in
Answer:
heyyyyyyyyy
Step-by-step explanation:
Free pionts thx
It is 1 16/25
Hope it helps ;-)
Ok it would be 1:23 p.m. i think
Answer:
-3 + -6= -9
because there is answer given
Divide 8 ft by 0.75, then divide by one third.