Answer:
p(x)= (x+1)(x+2)(x-3)(x-1)
then,multiplying two two terms
(x^2 +2x+x+2)(x^2-x-3x+3)
(x^2+3x+2)(x^2-4x+3)
x^4- 4x^3+3x^2 +3x^3-12x^2+9x+2x^2-8x+6)
x^4-x^3-7x^2+x+6
The coordinates to the second spot can be represented by the coordinates
(-12 + 3, 8 -11)
Since we are going 3 yards to the east we would be affecting the x-axis and since we are going east we will need to add 3 yards the x axis of the first spot
11 yards south would be affecting the y- axis negatively. We would need to subtract 11 from the y- axis of the first spot.
the coordinates of the second spot would be
-12 +3 = -9
8 -11 = -3
(-9, -3)
Answer:
#3: x is approximately 0.37, -5.37, #4: x is approximately 4.19, -1.19
Step-by-step explanation:
You can solve using the quadratic equation or by solving with the perfect square
= 
x is approximately 0.37, -5.37
Answer:
Step-by-step explanation:
