Answer:
0.85% probability that the first two are good and the last three are spoiled
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the first two jugs is not important, as is not the order in which the last three are selected. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
Desired outcomes:
2 spoiled, from a set of 43-11 = 32.
3 spoiled, from a set of 11.
So
Total outcomes:
5 jugs from a set of 43.
Probability:
0.85% probability that the first two are good and the last three are spoiled
20 degrees-> acute since less than 90
27 degrees-> acute since less than 90
133 degrees-> obtuse since more than 90
Domain: (-infinity, +infinity) Range: [0, +infinity)
Answer:
37 and 38.
Step-by-step explanation:
Let the smaller integer be x.
Thus, the larger integer is (x+1) since it is consecutive.
Subtract both sides by 1:
Divide both sides by 2:
To find the other number, simply add 1 to 37 to get 38.
I think the answer is 2( 4x+3)(x-2)