2 years ago

PLEASE HELP!

1 answer:

8 0

You have the function $y= \dfrac{60x}{1+0.625x}$ .
Rewrite it in the following way:

$y= \dfrac{60x}{1+0.625x}=\dfrac{60x}{1+ \frac{5}{8} x}=\dfrac{480x}{8+5x}=\dfrac{96\cdot 5x}{8+5x}=$
$=\dfrac{96(5x+8-8)}{8+5x}=\dfrac{96(5x+8)}{8+5x}-\dfrac{96\cdot8}{8+5x}=96-\dfrac{768}{8+5x}$ .
This function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.

From the added graph of the function you can conclude that the maximum number of moose that the forest can sustain at one time is 96.
Answer: Correct choice is A.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers

1. What is the solution to the system below? x+y=5 1x- y=3

Alika [10]

Answer:

(4,1)

Step-by-step explanation:

x+y=5

x- y=3

Add the equations together to eliminate y

x+y=5

x- y=3

--------------------

2x = 8

Divide each side by 2

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Now we can find y

x+y = 5

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Subtract 4 from each side

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