$\text{The domain}\\2x-6\neq0\ \wedge\ 6x-18\neq0\to x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2(x-3)}=\dfrac{9}{6(x-3)}\ \ \ |\cdot6\\\\\dfrac{3x^2}{x-3}=\dfrac{9}{x-3}\iff3x^2=9\ \ \ |:3\\\\x^2=3\to x=\pm\sqrt3$

4 0

2 years ago

Read 2 more answers

What is the volume, in inches, of this container? V = lwh

Vikki [24]

Answer:

12.25

Step-by-step explanation:

multiply the length, width, and height together as the formula for volume states.

5 0

2 years ago

What's the next step to substitution for this equation -4+y=-4

Marina86 [1]

Subtract the y then add the 4 to the other side so y=0

6 0

2 years ago

Help me with it plizz

Liono4ka [1.6K]

2x + 9 = -65
2x = -65 - 9
2x = -74
x = -74/2
x = -37

So, your final answer is -37

Hope this helps!

3 0

2 years ago