Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25
but is it an extraneous solution?
1 answer:
Step-by-step explanation:
To check if a solution is extraneous, simply plug it back into the original equation. If it works, then solution isn't extraneous.
√(2x−1) = 7
√(2(25)−1) = 7
√(50−1) = 7
√(49) = 7
7 = 7
So the solution isn't extraneous.
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