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2 years ago

What is the equation of the line that passes through the point (-4,4) and has a slope of -3

Mathematics

1 answer:

Arte-miy333 [17]2 years ago

3 0

Answer: y-4=-3(x+4) or y=-3x-8

Step-by-step explanation:

To find the equation of the line with a given point and slope, we can fill them into the point-slope formula. The point-slope formula is y-y₁=m(x-x₁).

y-4=-3(x-(-4)) [multiply]

y-4=-3(x+4)

Another equation could be slope-intercept form. It is y=mx+b.

y-4=-3(x+4) [distribute]

y-4=-3x-12 [add both sides by 4]

y=-3x-8

Now, we know that the equation is y=-3x-8 or y-4=-3(x+4).

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What is the value of x in the equation? 5 5/6 x + 2 2/3 = 12

devlian [24]

Answer:

The value of x is 8/5

Step-by-step explanation:

(35/6)x + (8/3) = 12

(35/6)x = 28/3 (cross multiplication)

105x = 168

x = 8/5

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2 years ago

Write an equation of the line in slope-intercept form. y=

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2 years ago

If ΔABC ≌ ΔRPQ , ∠A = 35˚, ∠C=75˚ , Find the measure of ∠Q. *

Norma-Jean [14]

<h3>Answer: angle Q = 75 degrees</h3>

Explanation:

The order of ABC and RPQ is important so we can match up the angles like so

angle A = angle R .... first letters
angle B = angle P .... second letters
angle C = angle Q ... third letters

Meaning that angle Q = 75 since angle C is this measure.

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3 years ago

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Number of solutions to a system of equations algebraic. How many solutions does the system have? Can someone help me please....

Svet_ta [14]

Answer:

A Exactly 1 solution

Step-by-step explanation:

if we express both equations as y = mx+b

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2 years ago

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Circle B has a center at point (0, 2) and a point W on the circle at (3, 3). Which equation represents a line that is tangent to

Solnce55 [7]

According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center $(x_0,y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, we have that the center is at point (0,2), hence:

$x^2 + (y - 2)^2 = r^2$

It goes through point (3,3), hence:

$3^2 + (3 - 2)^2 = r^2$

$r^2 = 10$

Hence, the equation is:

$x^2 + (y - 2)^2 = 10$

<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

$y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))$

Applying implicit differentiation, we have that:

$2x + 2y\frac{dy}{dy} = 0$

$\frac{dy}{dx} = -\frac{x}{y}$

Point W(3,3), hence:

$(x_0, y_0) = (3,3)$

$\frac{dy}{dx} = -\frac{3}{3} = -1$

Hence the equation is:

y - 3 = -(x - 3).

y = -x + 6.

More can be learned about the equation of a tangent line at brainly.com/question/8174665

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1 year ago