Yeah i think with a car or a plane:)
When in the melting process particles start to move more freely when in the freezing process particles tend to slow and vibrate in place
The answer is 4.0 kg since the flywheel comes to rest the
kinetic energy of the wheel in motion is spent doing the work. Using the
formula KE = (1/2) I w².
Given the following:
I = the moment of inertia about the
axis passing through the center of the wheel; w = angular velocity ; for the
solid disk as I = mr² / 2 so KE = (1/4) mr²w². Now initially, the wheel is spinning
at 500 rpm so w = 500 * (2*pi / 60) rad / sec = 52.36 rad / sec.
The radius = 1.2 m and KE = 3900 J
3900 J = (1/4) m (1.2)² (52.36)²
m = 3900 J / (0.25) (1.2)² (52.36)²
m = 3.95151 ≈ 4.00 kg
I believe the correct answer is expansion.
The net force on the bike and the rider is 120 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that:
F = ma
where
F is the net force exerted on an object
m is the mass of the object
a is its acceleration
For the bike and the rider in this problem, we have
m = 60 kg is their combined mass
is their acceleration
Therefore, the net force on them is
Learn more about Newton's second law:
brainly.com/question/3820012
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