Ask question

Ask question

All categories

2 years ago

9

Solve application using algebra. Write your equation or inequality and show your solving steps. The sum of 3 consecutive integer

s is 147. Find the 3 integers.

1 answer:

Mashcka [7]2 years ago

3 0

Answer:

Integers are 48, 49, 50

Step-by-step explanation:

x+(x+1)+(x+2) = 147

3x + 3 = 147

3x = 147-3

x = 144 / 3 = 48

You might be interested in

What is 2,000 10 times as much as

ankoles [38]

2000 has three zeros and 10 has one, so you add another zero to 2000 so it makes it 20,000

7 0

2 years ago

Read 2 more answers

Both students made a mistake.

Licemer1 [7]

Answer:

true answer I'm search in Goole

7 0

2 years ago

Read 2 more answers

Results from a survey conducted in a certain grocery store showed that 3 out of 5 people preferred crispy-flakes cereal to crunc

BabaBlast [244]

The number of people who how many most likely purchased crunchy-flakes cereal is 1000 customers.

<h3>How many most likely purchased crunchy-flakes cereal?</h3>

Ratio expresses the relationship between two or more numbers. It shows the number of times that one value is contained within other value(s).

The first step is to determine the ratio of people who preferred crunchy-flakes cereal:

Ratio of people who preferred crunchy-flakes cereal : 5 - 3 = 2

Now, multiply the ratio of those who prefer crunchy-flakes cereal by the total number of customers: (2/5) x 2500 = 1000 customers.

To learn more about ratios, please check: brainly.com/question/25927869

#SPJ1

5 0

1 year ago

19√$1143.8<br>can anyone solve this

IrinaK [193]

Well $19\sqrt{ $1143.8} = 19\sqrt{1143.8}$

Simplified would be: 642.58213482

642.58213482 = 642.58 = $642.58

Answer: <span>642.58

Hope this helps!

</span>

5 0

2 years ago

Given real numbers a,b > 1.

irina [24]

Answer:

FALSE

Step-by-step explanation:

Recall that a function f(x) is of exponential order c, if there exists a constant M such that and a real r such that

$|f(x)|\leq Me^{cx}\;(x\geq r)$

Now, take a = 2.5 and b = 2

The functions

$f(x)=(2.5)^x\;g(x)=2^x$

are both exponential of order 1, since

$\lim_{x \to \infty}\frac{f(x)}{e^x}=\lim_{x \to \infty}\frac{g(x)}{e^x}=0$

but a>b

8 0

2 years ago