All categories

2 years ago

Solve for X HELP ASAP

Mathematics

1 answer:

JulijaS [17]2 years ago

5 0

Answer:

x = 1

Step-by-step explanation:

set two sides equal to each other

these two sides are equal because the angles opposite them are equal.

8x = 5x + 3

x = 1

You might be interested in

6w^3 - 13 the GCF ? or is this a prime?

svetoff [14.1K]

It is a prime because the only other factor of 6w^3-13 is 1.

7 0

3 years ago

Hi help me with this too pls I can't pls

Musya8 [376]

Answer:

1) 3(9) +15

2) 2(-5)^2 - 11

3) (-2)^3 + 13(-2)

4) 4(6)^2 -7

5) (-9)^2 - (-9) + 10

All you have to do solve

Step-by-step explanation:

Replace the x with whatever number is in the f(number)

4 0

2 years ago

I NEED YALL’S HELP <br> 2x+12=64<br> Step by step

OverLord2011 [107]

Answer:

2x + 12 = 64

x = 26 (mark brain if this helps and is correct)

Step-by-step explanation:

to solve equations with one missing variable we must use the order of operations of equality

step 1: use the subtraction property of equality meaning subtract each side of the equation

ex: 2x + 12 - 12 = 64 - 12 (2x = 52)

step 2: use the division property of equality meaning divide each side of the equation by 2

ex: 2x/2 = 52/2 (x = 26)

step 3: check your answer by putting 26 as x because that is our answer

2(26) + 12 = 64 (multiply 2 * 26)

52 + 12 = 64 (add 52 + 12)

64 = 64 (if both sides of the equation are the same number like 64 = 64 then your answer is true meaning that x is equal to 26)

8 0

2 years ago

How many terms are in the polynomial abcd + e - fg + h 2?

Sphinxa [80]

There are four terms

8 0

2 years ago

Read 2 more answers

State the number of possible triangles that can be formed using the given measurements.

romanna [79]

Answer: 39) 1 40) 2

41) 1 42) 0

<u>Step-by-step explanation:</u>

39) ∠A = ? ∠B = ? ∠C = 129°

a = ? b = 15 c = 45

Use Law of Sines to find ∠B:

$\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o$

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36° ∠B = 15° ∠C = 129° is the only valid solution.

40) ∠A = 16° ∠B = ? ∠C = ?

a = 15 b = ? c = 19

Use Law of Sines to find ∠C:

$\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o$

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1: ∠A = 16° ∠B = 144° ∠C = 20°

Solution 2: ∠A = 16° ∠B = 4° ∠C = 160°

41) ∠A = ? ∠B = 75° ∠C = ?

a = 7 b = 30 c = ?

Use Law of Sines to find ∠A:

$\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o$

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13° ∠B = 75° ∠C = 92° is the only valid solution.

42) ∠A = ? ∠B = 119° ∠C = ?

a = 34 b = 34 c = ?

Use Law of Sines to find ∠A:

$\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o$

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0

2 years ago