All categories

2 years ago

What is the answer to +1 + -4=

Mathematics

2 answers:

ahrayia [7]2 years ago

8 0

The answer is -3.

If we add positive one/+1 to negative four/-4, we subtract +1 from -4, giving us -3.

dedylja [7]2 years ago

7 0

The answer is going to be -3.

Think of negative and positive like this; when you add, you move to the right on the number line. When you subtract, you move to the left.

With this, you have a positive number and you are taking away four. This means you move four spaces to the left.

This will be the same always!

I hope this helps you in the future!

You might be interested in

What is the length of AC?

Verizon [17]

AC is parallel to MN then triangle ABC and triangle MBN are similar and the ratio of the corresponding sides are equal...

3 0

2 years ago

10. The sum of two numbers is 13 more than twice the first number. Their difference is 14 less than the second number. Find each

Lynna [10]

The sum of two numbers is 13 more than twice the first number:

x + y = 2x +13

x - y = y - 14

solve the system of equations:

x - (x + 13) = (x +13) - 14

x = -12

y = 1

3 0

2 years ago

There are 25 quarts of water in a bucket. If you want to bottle it in 1/2 quart bottles, how many bottles do you have

nika2105 [10]

The answer will be 50 quarts using proportion and ratio

6 0

2 years ago

Read 2 more answers

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

2 years ago

Item 1 Find 11/12+(−7/12). Write your answer as a fraction in simplest form.

QveST [7]

Answer:

1/3

Step-by-step explanation:

I think not sure.

7 0

2 years ago