Question A: 14
Question B: 30min
Answer:
Step-by-step explanation:
we know that
To find the conjugate complex of a complex number, simply change the sign of the imaginary part of the complex number
In this problem we have
so
the complex conjugate is equal to
Evaluate 2x − 2 for x = 0, x = 1, and x = 2. Question 1 options: A) −1, 0, 2 B) −1, 1, 2 C) 0, 1, 2 D) 1, 2, 4
mixas84 [53]
The value of x in 2^x - 2 when x = 0, x = 1 and x = 2 are -1, 0 and 2 respectively. option A
<h3>Algebra</h3>
2^x - 2
when x = 0
2^x - 2
= 2^0 - 2
= 1 - 2
= -1
when x = 1
2^x - 2
=2^1 - 2
= 2 - 2
= 0
when x = 2
2^x - 2
= 2^2 - 2
= 4 - 2
= 2
Learn more about algebra:
brainly.com/question/4344214
#SPJ1
Answer:
2.33
Step-by-step explanation:
imagine a circle. its center is A, and it goes through B, so its radius is AB.
then it is important to know that the sum of all the angles in a triangle is 180 degrees.
one angle (at C) is 90. the angle at B is 25. so, the angle at A is 180 - 90 - 25 = 65 degrees.
more back to our circle.
in this circle the line CB is the sine of the angle at A multiplied by the radius.
and AC is the cosine of the angle at A multiplied by the radius.
we can ignore the orientation + and - of these functions, as we are only interested in the absolute length (and we can mirror the triangle, and all the angles and side lengths still stay the same).
=> CB = sin(A)×AB
AC = cos(A)×AB
=> 5 = sin(65)×AB
=> AB = 5 / sin(65)
=> AC = cos(65)×5/sin(65) = 5 × (cos(65)/sin(65)) =
= 5 × cot(65) = 2.33
