25m north east hope this helps
To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.
Here,
h = Depth average
= Density
Moreover,
Replacing,
Finally the force
Answer:
The magnitude of the electric field is 1.124 X 10⁷ N/C
Explanation:
Magnitude of electric field is given as;
where;
E is the magnitude of the electric field, N/C
q is the point charge, C
k is coulomb's constant, Nm²/C²
r is the distance of the point charge, m
Given;
q = 5mC = 5×10⁻³ C
r = 2m
k = 8.99 × 10⁹ Nm²/C²
Substitute these values and solve for magnitude of electric field E
Therefore, the magnitude of the electric field is 1.124 X 10⁷ N/C
Given :
Whole-body dose of 8.4 mGy from gamma-rays and 1.2 mGy from 80-Kev neutrons.
To Find :
The effective dose to a worker.
Solution :
By the given information effective dose to a worker is given by :
E.D = ( 8.4 × 1.2 × 0.12 ) + ( 1.2 × 1 × 1 )
E.D = 1.2096 + 1.2
E.D = 2.4096
Therefore, the effective dose to a worker is 2.4096 .
Answer:
Distance covered by Joe, d = 5 km
Explanation:
It is given that,
Speed of Joe, v = 20 km/hour
Time taken by Joe, t = 15 minutes = 0.25 h
We need to find the distance he is covering. It can be calculated using definition of speed as :
d = 5 km
So, Joe covers a distance of 5 km. Hence, this is the required solution.