Divide fractions by multiplying the first number by the reciprocal of the second.
2ay*15y= 30ay^2
5y^3*4a=20ay^3
(30ay^2)/(20ay^3)=3/(2y)
Final answer: 3/(2y)
Answer:
D as it is the obtuse
Step-by-step explanation:
At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless?
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
Answer:
First one is True, Second is false
Step-by-step explanation:
On Monday the absolute value was 2, on Tuesday the absolute value was 4. 2<4. Hope this helps
