Y = –3x + 5 y = mx + b Which values of m and b will create a system of linear equations with no solution? m = –3 and b = –3 m = 5 and b = –3 m = 3 and b = 5 m = -3 and b = 5
2 answers:
Answer:
m = -3 and b = -3
Step-by-step explanation:
y = –3x + 5 (1)
A system has no solution when we have an inconsistency. The case where an inconsistency remains is when m = -3 and b = -5. In the following way:
y = –3x - 3 (2)
if I multiply by -1 (2) and the add to (1). We have left
y = –3x + 5
-y = 3x + 3
0 = 0 + 8
And 0 is not equal to 8, therefore it is inconsistent.
Answer:
(A) m = –3 and b = –3
Step-by-step explanation:
If m=–3 and b=–3
The system of linear equations:
y = –3x + 5
y = mx + b
Becomes
y = –3x + 5 ......(i)
y = –3x – 3 .......(ii)
Notice that 5 is added to -3x in (i) and -3 is added to -3x in (ii) and both equals y. This is impossible. Thus the system has no solution.
You might be interested in
Step-by-step explanation:
5.4×-0.9=n
n=-4.86
(-4/5)/(1/3)=x
X=-2 2/5
Answer:
B i think
Step-by-step explanation:
Is something missing ???????????????????//
Answer:
From the plot it is clear that assumption 1 and 2 are violated. That is, the assumption of equal variance ( homoscedasticity) and there aren't any outliers.
Step-by-step explanation:
Both variables are quantitative and The relationship is linear have not been violated.
Answer:
Step-by-step explanation:
Three-fifths of the sum of 9 and f is = =