It is 24. You just add 3 each time. hope it helps!
Answer:
-1 5/8
Step-by-step explanation:
Let the total amount in the bowl be x;
If on Day 1, the volume of water in the bowl decreases by 7/8 cup, the remaining water will be;
x - 7/8
If on day 2, the volume in the bowl decreases by 3/4 cup, the remaining volume of water after the second day will be;
= x - 7/8 - 3/4
= x - (7-2(3))/8
= x - (7+6)/8
= x - 13/8
This shows that the total change after the two days is -13/8
As a mixed fraction;
-13/8 = -1 5/8
3(x+y)=y
y is not equal to zero
*Solution
1. The given equation is 3(x+y) = y and we are tasked to find the ratio between x and y. Distributing 3 to the terms in the parenthesis,
3(x+y) = y
3x + 3y = y
Transposing 3y to the right side OR subtracting 3y from both the left-hand side and the right-hand side of the equation would give
3x = -2y
Dividing both sides of the equation by 3,
x = (-2/3)y
Dividing both sides of the equation by y,
x/y = -2/3
Therefore, the ratio x/y has a value of -2/3 provided that y is not equal to zero.
Answer:
The third choice
Step-by-step explanation:
We need to find the slope and y-intercept of the line and then put it into y = mx = b form. To find the slope, pick a point on the line; I will use (-2, 5); count how many units up you need to go to get to the next point on the line, which in this case it would be 3. The count how many to the right or left you would need to go, which is 1 to the left. Moving left means a negative, so it is -1. Your slope fraction would be 
, since slope is rise over run. You can sub this fraction in for m in y = mx + b, which will give you a revised equation of y = -3x = b. To find the y intercept, or b, just find the point where the line crosses the y-axis, which is -1. So, the equation is now y = -3x - 1.The correct answer is third choice.
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Answer: 24$
Explanation:
72 / 6 = 12$
12$ for 1 ticket
12 x 2= 24$ for 2 tickets
I hope this helped!
<!> Brainliest is appreciated! <!>
- Zack Slocum
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
