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2 years ago

Steven has some money if he spends nine dollars then he will have 3/5 of the amount he started with

2 answers:

7 0

X - 9 = 3/5x
x - 0.6x = 9
0.4x = 9
x = 22.5
22.5 - 9 = 13.5

Therefore, Steven will have $13.50.
Im not entirely sure. You have to recheck this with someone else. Im having a brain fart right now lol

Vesna [10]2 years ago

5 0

Total money * fraction = part
$x* \frac{3}{5} =9 \\ ( \frac{5}{3}) * \frac{3x}{5} = 9* \frac{5}{3} \\ x= \frac{45}{3} =15$

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Which numbers are necessary to solve this problem?

Bad White [126]

Hello there.

Which numbers are necessary to solve this problem?

Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill.

How much time does Brian spend on the treadmill in 4 weeks?

Answer: 3 times a week, 45 minutes, 15 minutes, 4 weeks

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2 years ago

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Laci needs to put some logs in the back of her pickup truck. The dimensions of the truck bed are 8 feet by 5 .5 feet. What is th

Mazyrski [523]

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2 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago

Given a geometric sequence in the table below, create the explicit formula and list any restrictions to the domain.

Makovka662 [10]

Given:

The geometric sequence is:

$n$ $a_n$

1 -4

2 20

3 -100

To find:

The explicit formula and list any restrictions to the domain.

Solution:

The explicit formula of a geometric sequence is:

$a_n=ar^{n-1}$ ...(i)

Where, a is the first term, r is the common ratio and $n\geq 1$ .

In the given sequence the first term is -4 and the second term is 20, so the common ratio is:

$r=\dfrac{a_2}{a_1}$

$r=\dfrac{20}{-4}$

$r=-5$

Putting $a=-4,r=-5$ in (i), we get

$a_n=-4(-5)^{n-1}$ where $n\geq 1$

Therefore, the correct option is B.

5 0

2 years ago

Which expression equals 6x − 5y + 2 − 8x + 3( y + 5)? A) 3x − 2y + 17 B) −3x + 2y + 17 C) −2x − 2y + 17 D) −2x − 2y − 17

inysia [295]

Answer:

C) −2x − 2y + 17

Step-by-step explanation (PEMDAS):

First, we do 3 (y + 5) because of the parenthesis:

6x − 5y + 2 − 8x + 3y + 15

Since there are no exponents, multiplication ,or division, we will add and subtract. But we have to make sure we combine like terms. X with X's, Y with Y's and constants with constants. And ALWAYS go from left to right

6x − 5y + 2 − 8x + 3y + 15

−2x − 5y + 2 + 3y + 15

−2x − 2y + 2 + 15

−2x − 2y + 17.

8 0

2 years ago