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3 years ago

14

Ira wants to determine the fast food restaurant preferred by the majority of twelve year olds in his town. Which sample populati

on should he survey to get a random sample?
A.) Every third child that enters junior high school on a particular day.

B.) Every twelve year old that enters a particular hamburger restaurant in town.

C.) Every twelve year old that leaves a particular pizza restaurant in town.

D.) Every third twelve year old that leaves school on a particular day.

1 answer:

Kipish [7]3 years ago

5 0

The answer is D) because C) and B) are biased and would not be reasonable and A) has no guarantee of every third child being 12.

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Miss Gonzales opened an account with a deposit of $2,000,

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Answer:

i think its 18%

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2 years ago

Write y=-3/4 x-2 in standard form using integers.

jeyben [28]

Standard form is Ax + By = C

y = (-3/4)x - 2

Multiply both sides by 4.

4y = -3x - 8

Add 3x on both sides

3x + 4y = -8

Your final answer is 3x + 4y = -8.

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2 years ago

The table shows the height of 5 students in inches what is the mean absolute deviation for these numbers

german

Answer:

4

Step-by-step explanation:

To find the mean absolute deviation (MAD), first find the mean (or average).

μ = (59 + 71 + 68 + 75 + 67) / 5

μ = 68

Next, subtract the mean from each value and take the absolute value.

|59 − 68| = 9

|71 − 68| = 3

|68 − 68| = 0

|75 − 68| = 7

|67 − 68| = 1

Sum the results and divide by the number of students.

MAD = (9 + 3 + 0 + 7 + 1) / 5

MAD = 4

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2 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

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2 years ago

Solve the system by substitution.<br> y = x<br> y = 2x – 8

m_a_m_a [10]

Answer:

y=8

x=8

Step-by-step explanation:

y=2y-8

-y=-8

y=8

x=8

6 0

2 years ago

Read 2 more answers