Answer:
Edie has a better deal since his final price is lower
Step-by-step explanation:
Cousin Edie drank all of Clark's egg nog . Edie finds a coupon for 50 cents off that can only be use at a local grocery store.Clark normally buys his egg nog at the supermarket.
The tax rate at both stores is 2.25%.
Clark buys the egg nog at $5.95 plus tax .
Edie buys the egg nog at $6.35 plus coupon plus tax.
After Edie applies the coupon , the final price is $( 6.35 - 0.50 ) = $5.85
<u>Since the percentage of tax applied is the same, the deal with lower final price is better.</u>
Hence, Edie has a better deal.
<em>∙•❁ </em>Okay time to solve this Step-By-Step.<em>❁•∙ </em>
16−<span>2n</span>−5+<span>8n</span>=<span>65
<em>∙•❁ </em>So the first part we need to Simplify both sides of this equation, so:
<span><span><span><span>16−<span>2n</span></span>−5</span>+<span>8n</span></span>=65
<em>∙•❁ </em>We are going to simplify this Step-By-Step.
<span><span><span><span>16−<span>2n</span></span>−5</span>+<span>8n</span></span>=65
</span><span><span><span><span><span><span>16+</span>−<span>2n</span></span>+</span>−5</span>+<span>8n</span></span>=65
<em>∙•❁ </em>Combine like terms:
</span><span><span><span><span>
(<span><span>−2n</span>+8n</span>)</span>+<span>(<span>16+−5</span>)</span></span>=65 </span>
<span><span>6n+11</span>=65
</span><span><span><span>6n</span>+11</span>=65
<em>∙•❁ </em>Now subtract 11 from both sides.
<span><span><span><span>6n</span>+11</span>−11</span>=<span>65−11
</span></span><span><span>6n</span>=54
<em>∙•❁ </em>Now divide both sides by 6 and you'll get your answer:
6n/6=54/6
<em>∙•❁ </em>Your final answer is:
n=9
<em>∙•❁I hope this helps!❁•∙ </em> </span></span></span></span></span>
Answer:
m= - 1/4
Step-by-step explanation:
Answer:
x=-28
Step-by-step explanation:
you multiply the number first
and you calculate
then you move constant to the right
you changes the sign
done!
Answer:
these are true = 1, 3, 5
Step-by-step explanation:
overall class a scored better than class b
they're more students in class a compared to class b
