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2 years ago

Graham and Hunter are circus performers. A cable lifts Graham into the air at a constant speed of 1.5 ft/s. When Graham's

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

8 0

Answer:

Answer A on Ed

Step-by-step explanation:

Test

denis23 [38]2 years ago

7 0

Answer:

If Hunter is right beneath Graham ( 18ft-5ft=13ft) and G's arms are 18ft above ground ( and going up, no bending) the question would be at what hight would Graham catch the ball and and how soon.

The maximum hight that the ball can reach before falling ( when the vector F - force of throwing the ball to Graham, would be equal in module to gravitational force - considering gravitational velocity of 13ft/s^2

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Tom started his hike at 2:15pm. he arrived at his destination at 4:30pm. how long did he hike??

Alex

Answer:2:15 minutes is how long he hiked

Step-by-step explanation:

8 0

1 year ago

Read 2 more answers

A competitive diver dives from a 33-foot high diving board. The height of the diver in feet after 't' seconds is given by u(t) =

ludmilkaskok [199]

Answer:

$t = 0.375s$

Step-by-step explanation:

Given

$h(t) = -16t^2 + 4t + 33$ --- driver 1

$Rate = 2ft/s$ -- driver 2

$height = 33ft$

Required

The time they passed each other

First, we determine the function of driver 2.

We have that:

$Rate = 2ft/s$ and $height = 33ft$

So, the function is:

$h_2(t) = Height - Rate * t$

$h_2(t) = 33 - 2t$

The time they drive pass each other is calculated as:

$h(t) = h_2(t)$

$-16t^2 + 4t + 33= 33 - 2t$

Collect like terms

$-16t^2 + 4t + 2t= 33 - 33$

$-16t^2 + 6t= 0$

Divide through by 2t

$-8t + 3= 0$

Solve for -8t

$-8t = -3$

Solve for t

$t = \frac{-3}{-8}$

$t = 0.375s$

7 0

2 years ago

Factor x^2 + 25 in the complex numbers

zzz [600]

This expression cannot be factored with rational numbers. The polynomial is not factorable with rational numbers.

7 0

3 years ago

Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with

worty [1.4K]

Answer:

$z$

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu =26$ kilograms and standard deviation $\sigma=4.2$ kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

$X$ "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(26,4.2)$

Where $\mu=26$ and $\sigma=4.2$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

$z=\frac{42.6-26}{4.2}=3.95$

So then the corresponding z scale would be:

$z$

7 0

2 years ago

Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn

ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0

2 years ago