Answer:
50 of D and 10 of C
Step-by-step explanation:
First of all, put this data into 2 equations.
You sold 60 items, so C+D=60
C is $5 so we can represent it by 5C
D is $7 so we can represent it by 7D
You made $400 total from C and D, so 5C+7D=400
We can use simultaneous equations to solve this.
To eliminate one of these variables, we'll multiply the first one by 5 to make it 5C like the other.
5(C+D=60) (make sure you multiply both sides.)
so 5C+5D=300
5C+7D=400
Now we solve it:
5C-5C+7D-5D=400-300
7D-5D=100
2D=100
D=50
Now we can substitute this with one of the equations to find C
C+50=60
C=60-50
C=10
so, (10x5)+(50x7)=400
The type of statement is a congruent
Step-by-step explanation:
x-5x-6=0
x-5x=6+0
4x=6
x=6
4
x=3
2
<h2>this may help you</h2>
2x+3(5-x)-12=4(x+2)
Distribution property:
2x+15-3x-12=4x+8
Add like terms:
-1x+3=4x+8
Add 1x to both sides:
3=5x+8
Subtract 8 from both sides:
-5=5x
Divide by 5 on both sides to get x by itself:
x= -1
Set up a proportion to describe this relationship. So, for every 2 cats, there is five dogs. Therefore, “c” can represent your unknown quantity for every 35 animals.
2/5 = c/35
Cross multiply, multiplying the numerator/top number of the first fraction/ratio, by the denominator/bottom number in the second fraction/ratio.
2 • 35 = 70
Then, Cross multiply, multiplying the numerator/top number of the second fraction/ratio, by the denominator/bottom number in the first fraction/ratio.
C • 5 = 5c
So, now the problem shows both products as equal to each other.
70 = 5c
To solve for the variable, “c”, you must isolate the variable, by performing the opposite/inverse operation of multiplication, since that will undo the multiplication, for the variable to stand alone. Therefore, divide both sides of the equation by 5.
70/5 = 5c/5
14 = c
So, there is 14 cats out of 35 animals.
