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2 years ago

If the sum of three consecutive numbers is 852, what is the middle one?

Mathematics

1 answer:

denis-greek [22]2 years ago

5 0

Divide the total by the quantity of numbers:

852/3 = 284

Because there are an odd quantity of numbers (3) the answer is the middle number.

The answer is 284

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100 POINTS FOR BOTH SIDES PLZZZ Plzzz help me with this SIDES

Oliga [24]

Answer:

Step-by-step explanation:

point = (x, y)

A = ( $1\frac{1}{2}$ , 12)

B = ( $2\frac{1}{2}$ , 20)

C = (3, 24)

D = ( $3\frac{1}{2}$ , 28)

y/x ratios

$\frac{12}{1\frac{1}{2} }$

$\frac{20}{2\frac{1}{2} }$

24/3

$\frac{28}{3\frac{1}{2} }$

(1 2/3, 3 1/3) = 3 1/3 ÷ 1 2/3 = 2

(1 1/4, 2 1/2) = 2 1/2 ÷ 1 1/4 = 2

(3, 7) = 7 ÷ 3 = 2 1/3

(4 1/2, 9) = 9 ÷ 4 1/2 = 2

The ratio 7/3 (x = 3 and y = 7) is not proportionally related to the others.

The other ratios are equal to each other and are therefore in proportion.

7. yes

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1 year ago

I need help with this

Aliun [14]

-55+13= -42

94i -12i = 82i

answer = -42+82i

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2 years ago

Ax-by=c I need help solving this problem

telo118 [61]

Solving for x.
Add by to both sides
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2 years ago

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stira [4]

A quotient of a number 21 is 3 and 63
Hope this helps!

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2 years ago

Which is a factor of 2x^2y^4-10x2y+14y3-70

VARVARA [1.3K]

2x^2y(y^3-5)+14(y^3-5)
(2x^2y)+14(y^3-5)
2(x^2y+7)(y^3-5)
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2 years ago