The nearest thousand is 547,000
Answer:
The time interval when is at
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between
The schematic free body graphical representation of the above illustration was attached in the file below and the point when is at 4 is obtained in the parabolic curve.
So, is at
Taking the integral of the time interval in order to determine the distance; we have:
distance =
=
= By using the Scientific calculator notation;
distance = 106.109 m
(-36x^4y+144x²y^6) / (-4x²y) =
36xy*(x³+4xy^5) / (-4x²y) =
-9*(x³+4xy^5) / x
Factor out -4
-4(x^3+3x^2-2x-6
Factor out x^2
-4(x^2(x+3)-2x-6)
Factor out -2
-4(x^2(x+3)-2(x+3))
Factor out x+3
-4(x+3)(x^2-2)
Answer:
I think the answer is 155 ft^2. Hope this helps.