Isobaric transition, first law: <span>H=ΔU+w</span>
for a gas expansion: <span>w=<span>P<span>ext</span></span>∗ΔV</span>
to convert to joules, you need the gas constants.
R = 0.08206 L atm/mol*K, R=8.314 J/mol*K
<span>w=<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span></span>
<span>ΔU=ΔH−[<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span>]</span>
<span>ΔU=−75000 J−[(43.0atm)∗(2−5)L∗<span><span>8.314 J</span><span>0.08206 L atm</span></span>]</span>
Then you need to convert to kJ.
by the way U=E, internal energy.
Aretes and horns
Explanation:
Aretes and horns are the landforms that are created where cirques meet. These landforms are products of glacier erosion in most temperate and polar regions.
- Cirques are common products of alpine glacier erosion.
- They arise in form of bowl shaped hollows on the side of a mountain.
- These hollows joins to form a U-shaped valley called Aretes and unique pointed arcs known as horns.
Learn more:
factors that affects erosion brainly.com/question/2473244
#learnwithBrainly
Hmmm I’m not sure just to to quizlet for now but that seems kinda like science and elements
Answer:
Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.
Explanation:
Glycogen is the form that glucose is stored in human body.
Cellulose is the structural part of plant cell walls and human cannot digest it.
Amylose is the polysaccharide linked mainly by the the bonds of 1,4 glycosidic.
Cellulose is an unbranched polysaccharide linked mainly by the bonds of 1,4 glycosidic.
Amylopetin and Glycogen are branched polysaccharides linked by the bonds of 1,4 glycosidic and 1,6 glycosidic.
Amylopetin and Cellulose are mainly stored in plants.
Answer:
F. 2NO + 02 —> 2NO
H. 4NH3 + 502 —> 4NO + 6H20
Explanation:
The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.
2NO + 02 —> 2NO
From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.
4NH3 + 502 —> 4NO + 6H20
From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.
The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.
This is certified by the law of conservation of mass.
The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side