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2 years ago

The legs of a right triangle measure 70 centimeters and 64 centimeters.

Mathematics

1 answer:

mario62 [17]2 years ago

5 0

Answer:

94.85

Step-by-step explanation:

use pytagorian theorem

c^2=a^2+b^2

You might be interested in

What is 2.75 rounded to the nearest hundredth

almond37 [142]

Well first off we need to know how to round or what rounding is. Rounding is the approximation of numbers usually decimals to a approximate cut off number for numbers that are too long or hard to work with/remember. To round a number you simply need to look at the number behind that number whether its a whole number (integer) or a decimal, either one will work. Now continuing on (on) how to round the number, look at the number after it and if it is 5 or above the number rounds up +1 and all numbers behind that turn to 0. For example 3.25500 round to the nearest hundredth, 3.26(000). Now if the number is 4 or smaller then you don't do anything at all (no rounding) and all the numbers after the being rounded number turn to 0's like so, 3.254(0000) rounded to the nearest hundredth, 3.25(00000). So now that we know how to round and what rounding is we need to look at are hundredth place on are number here and see what the next number is after that, in this case it is 0 because there is no stated number there the default next number is 0 like so,
2.750 and because 0 is under 5 we don't do any rounding at all here and just leave it as it is. So 2.75 rounded to the nearest hundredth is 2.75

Enjoy!=)

4 0

2 years ago

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by

11111nata11111 [884]

Answer:

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is $V=l\times b\times h$

$V=(11-2x)\times (7-2x)\times x$

$V=4x^3-36x^2+77x$

Derivate w.r.t x,

$V'(x)=4(3x^2)-2(36x)+77$

$V'(x)=12x^2-72x+77$

The critical point when V'(x)=0

$12x^2-72x+77=0$

Solve by quadratic formula,

$x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}$

$x=4.607,1.392$

Derivate again w.r.t x,

$V''(x)=24x-72$

Now, $V''(4.607)=24(4.607)-72=38.568>0$ (+ve)

$V''(1.392)=24(1.392)-72=-38.592$ (-ve)

So, there is maximum at x=1.392.

The length of the box is $l=11-2x$

$l=11-2(1.392)=8.216$

The breadth of the box is $b=7-2x$

$b=7-2(1.392)=4.216$

The height of the box is h=1.392.

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is $V=l\times b\times h$

$V=8.216\times 4.216\times 1.392$

$V=48.217\ in.^3$

The volume of the box is 8.217 cubic inches.

5 0

2 years ago

What is the volume of a cylinder with a radius of 3 inches and a height of 5 inches ? Rounded to the nearest tenth .

Arisa [49]

Answer:

141.4

Step-by-step explanation:

Plug the numbers into the formula, V=πr2h, you know that your radius is 3 and your height is 5, so you get V=π(3)2(5), you just then put it in the calculator. You get 141.37, round to the nearest tenth 141.4

8 0

2 years ago

Read 2 more answers

The steps below show the incomplete solution to find the value of m for the equation 5m − 2m + 4 = −1 + 12: Step 1: 5m − 2m + 3

Delicious77 [7]

Given:

Consider the equation is:

$5m-2m+3=-1+12$

Some steps of the solution are given.

To find:

The next step of the solution.

Solution:

Step 1: The given equation is:

$5m-2m+3=-1+12$

Step 2: Simplifying right hand side.

$5m-2m+3=11$

Step 3: Simplifying left hand side.

$3m+3=11$

These steps are already given. So, the next step is:

Step 4: Subtracting 3 from both sides.

$3m=8$

Therefore, the correct option is (b).

8 0

2 years ago

Need Help! I don't get it

serious [3.7K]

Well hmmm let's say you take the car and go in the city for 60 miles with it, well, the car can do 60 miles per gallon, since you just drove it for 60 miles, you only spent 1 gallon of gasoline then.

that only happens if you drive it for 60 miles, what if you drive it for more, let's do a quick table on that,

$\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
60&3.6(1)\\\\
&3.6\left( \frac{60}{60} \right)\\\\
120&3.6(2)\\\\
&3.6\left( \frac{120}{60} \right)\\\\
180&3.6(3)\\\\
&3.6\left( \frac{180}{60} \right)
\end{array}$

and so on, now let's check if you less than 60 miles,

$\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
40&3.6\left( \frac{40}{60} \right)\\\\
20&3.6\left( \frac{20}{60} \right)\\\\
10&3.6\left( \frac{10}{60} \right)
\end{array}$

so, if you divide the amount of miles driven, by 60, when you have driven it for 120 miles, 120/60 is just 2, and the cost is for 2 gallons, or 3.6 * 2, which is 7.2 bucks, for 180 miles is 180/60 or 3 gallons for 3.6 * 3 bucks, and so on.

now, what if you drive it instead for "m" miles?

$\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
m&3.6\left( \frac{m}{60} \right)\\\\
\end{array}\implies c=3.6\left( \cfrac{m}{60} \right)\implies c=\cfrac{3.6m}{60}
\\\\\\
c=\cfrac{3.6}{60}m\implies c=0.06m$

3 0

2 years ago