Answer:
Clouds, Sweater Weather, and Bestfriend also So what.
Post Malone Radio.
Answer:
i would say 1.111111111111 you get it it keeps going
Answer:
On the first one the total is 37500.The second dealer is again,37500.You put a coma after every 3 digit so the coma is 357,000.Sorry if I over explained it.
Answer:
We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489
Step-by-step explanation:
- Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.
This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.
However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.
Observe that:
- 1+2+4+8+16+32+64+128+256+489=1000
- Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
- If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since , by 2) we know that this would be possible.
Answer:
-23x^3+20x^4+25x^2+84x-84
Step-by-step explanation:
1 Expand by distributing sum groups.
4x^2(3x+5x^2-6)-7x(3x+5x^2-6)+14(3x+5x^2-6)
2 Expand by distributing terms.
12x^3+20x^4-24x^2-7x(3x+5x^2-6)+14(3x+5x^2-6)
3 Expand by distributing terms.
12x^3+20x^4-24x^2-(21x^2+35x^3-42x)+14(3x+5x^2-6)
4 Expand by distributing terms.
12x^3+20x^4-24x^2-(21x^2+35x^3-42x)+42x+70x^2-84
5 Remove parentheses.
12x^3+20x^4-24x^2-21x^2-35x^3+42x+42x+70x^2-84
6 Collect like terms.
(12x^3-35x^3)+20x^4+(-24x^2-21x^2+70x^2)+(42x+42x)-84
7 Simplify.
-23x^3+20x^4+25x^2+84x-84