Width of the rectangle is 9 units
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units
Area of the rectangle = length × width
54 = x (x - 3)
54 = x² - 3x
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)
x(x + 6) - 9(x + 6) = 0
(x + 6)(x - 9) = 0
x = -6, 9 (negative value is neglected)
x = 9 units
Answer:
the answer would be choice A
Answer:
x=-1
Step-by-step explanation:
4(x-3(-2))=6(x-3(-2)) => 4(x+6)=6(x+6) => 4x+24=6x+26 => -2=2x => x=-1
Answer:
non lo so
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
13 ≤ 4n if n = 3
13 ≤ 12
Is this true?
First of all this symbol (≤) means
- Less than
- Equal to
Is 13 less than 12?
No
Is 13 equal to 12?
No
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-Chetan K
