To solve problem 19, we must remember the order of operations. PEMDAS tells us that we should simplify numbers in parentheses first, exponents next, multiplication and division after that, and finally addition and subtraction. Using this knowledge, we can begin to simplify the problem by working out the innermost set of parentheses:
36 / [10 - (3-1)²]
36 / [10 - (2)²]
Next, we should still simplify what is inside the parentheses but continue to solve the exponents (the next letter in PEMDAS).
36/ (10-4)
After that, we should compute the subtraction that is inside the parentheses.
36/6
Finally, we can solve using division.
6
Now, we can move onto problem 20:
1/4(16d - 24)
To solve this problem, we need to use the distributive property, which allows us to distribute the coefficient of 1/4 through the parentheses by multiplying each term by 1/4.
1/4 (16d-24)
1/4(16d) - 1/4(24)
Next, we can simplify further by using multiplication.
4d - 6
Therefore, your answer to problem 19 is 6 and the answer to problem 20 is 4d -6.
Hope this helps!
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Let when i is the element itself is allocated to 'j'
Min
Subject to:
Answer:
1 x=-2.5 y = -5.5
2. x=5 y=1
Step-by-step explanation:
1) What is the solution of the given system?
5x-y=-7
3x-y=-2
Multiply the second equation by -1
-1*(3x-y)=-1(-2)
-3x +y = 2
Now add the first equation to the modified second equation
5x-y=-7
-3x +y = 2
------------------
2x = -5
Divide each side by 2
2x/2 = -5/2
x = -2.5
Now we need to find y
-3x+y =2
-3(-2.5) +y =2
7.5 +y =2
Subtract 7.5 from each side
7.5 -7.5 +y =2-7.5
y = -5.5
2) what is the solution of the given system?
5x+7y=32
8x+6y=46
Divide the second equation by 2
8x/2+6y/2=46/2
4x+3y =23
Multiply the first equation by 4
4 (5x+7y)=32*4
20x+28y = 128
Now multiply the modified 2nd equation by -5
-5(4x+3y )=-5(23
)
-20x -15y = -115
Lets add the new equations together to eliminate x
20x+28y = 128
-20x -15y = -115
---------------------
13y = 13
Divide each side by 13
13y/13 =13/13
y=1
Now substitute back in to find x
5x+7y=32
5x +7(1) =32
5x +7 =32
Subtract 7 from each side
5x+7-7 =32-7
5x =25
Divide by 5
5x/5 =25/5
x=5
Answer:
1. SSS; Triangle ABC is congruent to Triangle DEF; sorry there's no triangle symbol on here.
2. HL; CBA is congruent to ZYX; or ABC is congruent to XYZ
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
The relevant rules of exponents are ...
(a^b)^c = a^(bc)
a^-b = 1/a^b
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