Answer:
C ) 1.70 g/L
Explanation:
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Also,
Moles = mass (m) / Molar mass (M)
Density (d) = Mass (m) / Volume (V)
So, the ideal gas equation can be written as:
PM=dRt
At STP,
Pressure = 1 atm
Temperature = 273.15 K
Molar mass of fluorine gas = 38 g/mol
Applying the equation as:
1 atm × 38 g/mol = d × 0.0821 L.atm/K.mol × 273.15 K
<u>⇒d = 1.70 g/L</u>
Al₂O has a higher percentage of aluminium.
Explanation:
To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:
Molar mass of Al₂O = 2(27) + 16 = 70g/mol
Molar mass of Al(NO₃)₃ = 27 + 3[14 + 3(16)] = 213g/mol
Percentage by mass of Al in Al₂O = 
x 100 = 77%
Percentage by mass of Al in Al(NO₃)₃ = 
x 100 = 12.7%
Al₂O has a higher percentage of aluminium.
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Molar mass brainly.com/question/2861244
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Answer:
2Zn + 2HCI ➡️ ZnCI2 + H2
LHS of equation
Z = 2
H = 2
Cl = 2
RHS of equation
Zn = 1
Cl =2
H =2
as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass
Explanation:
the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.
