The given equation is:
a = 3b^2 + 2
For this case, what you should do is write carefully each term that belongs to the equation.
a is equal to three times b squared plus two.
answer:
a is equal to three times b squared plus two.
C. 4<=C<=12
Hope that helps
I'm just gonna assume that 6/3 and 1/2 are fractions.
First you have to find common denominators for the fractions to be added.
The first common denominator divisible by both the denominators is 6.
So 2x3=6 and 1x3=3
and 3x2+6 and 6x2+12
so that would be 12/6 + 3/6
Then you would proceed to add both of the numerators together which are 12 and 3.
To get a total of 15/6. You can also simplify that into a mixed number 2 1/2.
35 because if you half the amount of salads he's eaten (seeing as he eats one burger for every two salads) then the extra one is the first salad in the cycle.
Answer:
1 x=-2.5 y = -5.5
2. x=5 y=1
Step-by-step explanation:
1) What is the solution of the given system?
5x-y=-7
3x-y=-2
Multiply the second equation by -1
-1*(3x-y)=-1(-2)
-3x +y = 2
Now add the first equation to the modified second equation
5x-y=-7
-3x +y = 2
------------------
2x = -5
Divide each side by 2
2x/2 = -5/2
x = -2.5
Now we need to find y
-3x+y =2
-3(-2.5) +y =2
7.5 +y =2
Subtract 7.5 from each side
7.5 -7.5 +y =2-7.5
y = -5.5
2) what is the solution of the given system?
5x+7y=32
8x+6y=46
Divide the second equation by 2
8x/2+6y/2=46/2
4x+3y =23
Multiply the first equation by 4
4 (5x+7y)=32*4
20x+28y = 128
Now multiply the modified 2nd equation by -5
-5(4x+3y )=-5(23
)
-20x -15y = -115
Lets add the new equations together to eliminate x
20x+28y = 128
-20x -15y = -115
---------------------
13y = 13
Divide each side by 13
13y/13 =13/13
y=1
Now substitute back in to find x
5x+7y=32
5x +7(1) =32
5x +7 =32
Subtract 7 from each side
5x+7-7 =32-7
5x =25
Divide by 5
5x/5 =25/5
x=5
