I will show you a method to find a velocity of anything:-
Find average velocity when acceleration is constant.
Set up an equation with position and time instead.
Find the distance between the start and end points.
Calculate the change in time.
Divide the total displacement by the total time.
Solve problems in two dimensions.
The answer is: C. 0.00427 m.
A) 1 km = 1000000 mm.
d = 0.0000427 km · 1000000 mm/km.
d = 47.7 mm.
B) 1 hm = 100000 mm.
d = 0.000427 hm · 100000 mm/hm.
d = 42.7 mm.
C) 1 m = 1000 mm.
d = 0.00427 m · 1000 mm/m.
d = 4.27 mm.
D) 1 cm = 10 mm.
d = 4.27 cm · 10 mm/cm.
d = 42.7 mm.
Millimeter (abbreviated: mm, a thousandth part of metar) is an unit of distance in the metric system.
night vision glasses detect energy
Gases near together and vibrate in position however, don't circulate beyond each other. In a liquid, the particles are interested in every different but now not as a great deal as they may be in a strong.
The particles of a liquid are near together, constantly transferring, and may slide beyond one another. The Kinetic-molecular concept attempts to explain the behavior of fuel molecules based totally on the nature of gasoline. The principle is grounded on simple assumptions
In gases the debris passes swiftly in all directions, regularly colliding with every different facet of the box. With a boom in temperature, the debris gains kinetic strength and passes more quickly. Gasoline is a state of matter that has no constant form and no fixed extent. Gases have a decreased density than other states of the count, together with solids and liquids. there may be a high-quality deal of empty area between debris, that have loads of kinetic energy and aren't especially drawn to one another.
Learn more about the behavior of particles here:-brainly.com/question/2456191
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The question is incomplete, the complete question is;
1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?
A. CL2
B. SF6
C. Kr
D. UF6
E. Xe
Answer:
SF6
Explanation:
From Graham's law;
Let the rate of diffusion of oxygen be R1
Let the rate of diffusion of unknown base be R2
Let the molar mass of oxygen by M1
Let the molar mass of unknown gas be M2
Hence;
R1/R2 = √M2/M1
So;
2.14/1 = √M2/32
(2.14/1)^2 = M/32
M= (2.14/1)^2 × 32
M= 146.6
This is the molar mass of SF6 hence the answer above.