What is the solution to the equation 9 cubed x ≈ 7?

Mathematics

1 answer:

yulyashka [42]2 years ago

4 0

Answer

7/729

Explanation

The question requires to you to find the value of x.

9³x = 7

729 x = 7

x = 7/729

You might be interested in

Factor the polynomial by its greatest common monomial factor. 3b^5+15b^4−18b^7

Natasha2012 [34]

Answer:

Step-by-step explanation:

3b⁵ + 15b⁴ - 18b⁷ = 3b⁵ + [3*5*b⁴] - [6*3*b⁷]

=3b⁴*( b + 5 - 6b³)

3 0

2 years ago

What is the volume of the pyramid? PF

Sergeeva-Olga [200]

Volume = 1/3 * area of base * height
= 1/3 * 11^2 * 12
= 484 cm^3

4 0

2 years ago

Solve using algebraic equation: 5sin2x=3cosx (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .