The answer to the whole process. is2
Since you're only interested in x, you can use the first equation to write an expression for y that can be substituted into the second equation.
.. y = k -x
.. 2x +3(k -x) = k +1
.. -x +3k = k +1 . . . . . collect terms
.. 2k -1 -x = 0 . . . . . . subtract k+1
.. 2k -1 = x . . . . . . . . .add x
The 3rd selection is appropriate.
Answer:
34.5
Step-by-step explanation:
<u><em>Statement B. Is correct.</em></u>
Answer:
It is not a good model because neither point lies on the line.
Step-by-step explanation:
We can test each point on the equation of the line.
7x - 10y = 3
Point: (8, 5)
7(8) - 10(5) = 56 - 50 = 6
The left side equals 6, not 3, so point (8, 5) is not on that line.
Point: (-12, -9)
7(-12) - 10(-9) = -84 + 90 = 6
The left side equals 6 again, but the right side is 3, not 6.
Answer: It is not a good model because neither point lies on the line.
