X - 2y = 3
<span>4x^2 - 5xy + 6y = 3
lets solve for x the first and substitute in the second:
x = 3 + 2y
4(</span>3 + 2y)^2 - 5(3 + 2y)y + 6y = 3
4(9 + 12y + 4y^2) - 15y - 10y^2 = 3
36 + 48y +16y^2<span> - 15y - </span><span>10y^2 = 3
6y^2 + 33y + 33 = 0
we can solve using the general quadratic formula:
y = (-33 +- </span>√(33^2 - 4*6*33)<span>)/12
</span>y = (-33 +- √(297)<span>)/12
</span>so there are 2 solutions for y:
y1 = (-33 + √(297)<span>)/12
</span>y2 = (-33 - √(297)<span>)/12
</span>pick one and then substitute the y value in the first equation to find x
Answer:
a and c
Step-by-step explanation:
The equation of a quadratic in vertex form is
f(x) = a (x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
f(x) = (x - 5)² + 7 ← is in vertex form
Thus the function is quadratic → a
• If a > 0 then the grapg will open upwards
• If a < 0 then the graph will open downwards
Here a = 1 > 0 then graph will open upwards → c
9514 1404 393
Answer:
5/3
Step-by-step explanation:
The prime factorizations are ...
10 = 2·5
12 = 2·2·3
Then *10* = 5 and *12* = 3, so *10*/*12* = 5/3.
Answer:
1,735-3
Step-by-step explanation:
It said decreases so it would be subtracted
