9514 1404 393
Answer:
a) 14√5 feet
b) about 31.3 feet
Step-by-step explanation:
a) The 42-ft hose is the hypotenuse of a right triangle with one leg 28 ft. We are asked to find the other leg. The Pythagorean theorem is useful.
h² +(28 ft)² = (42 ft)²
h² = (1764 -784) ft² = 980 ft²
h = √(196·5) ft
h = 14√5 ft
__
b) The approximate height is ...
14√5 ≈ 31.305, about 31.3 feet
Answer:
Graph attached.
Step-by-step explanation:
y > 
x + 3
When x = 0 , y = 3
When y = 0 , x = -4.5
Graphing the two points (0, 3) and (-4.5, 0) gives the graph attached below:
The shaded part is the wanted region.
Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
The question was not typed correctly. Here, a better version:
<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary. </em>
<em>
</em>
<em>Y=s^2/36 and y=5.7;14.3 ft
</em>
<em>Y=5.7s^2 and y=36; s=2.5ft
</em>
<em>Y=36s^2 and y=0; s=0.4 ft
</em>
<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>
In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:
Y=s^2/36
with y = 5.7
5.7 = s^2/36
5.7*36 = s^2
√205.2 = s
14.3 ft
I think it’s B if not I can’t tell because I can’t see all the questions .
Answer:
100 J
Step-by-step explanation:
The formula for kinetic energy is as follows:
where
KE= kinetic energy (J)
m= mass (kg)
v= velocity (m/s)
Given: m= 50 kg, v= 2 m/s
Substituting the given information into the formula:
KE
= ½(50)(2²)
= ½(50)(4)
= 100 J
