The one fact that needs to be mentioned but isn't given anywhere on or around the graph is: The distance, on the vertical axis, is the distance FROM home. So any point on the graph where the distance is zero ... the point is in the x-axis ... is a point AT home.
Segment D ...
Walking AWAY from home; distance increases as time increases.
Segment B ...
Not walking; distance doesn't change as time increases.
Segment C ...
Walking away from home, but slower than before; distance increases as time increases, but not as fast. Slope is less than segment-D.
Segment A ...
Going home; distance is DEcreasing as time increases. Walking pretty fast ... the slope of the line is steep.
Answer:
It would be PE=16kg * 9.8 m/s^2 * 1m = 160 J
Explanation:
The person who asked this question ended up answering his own question so I'm here to let you know all that the answer was founded by the person whos posted the question himself full credit goes to him :)
Any object that is given any initial velocity and which follows a path due to gravitational force acting on it and by the frictional resistance of the atmosphere is called a projectile. This is because the object is projected and not influenced by anything except gravity.
Answer:
option A
Explanation:
given,
depth of the sea level = 10 m
g = 10 m/s²
Pressure underwater = ?
we know,
P = ρ g h
where ρ is the density of water which is equal to 1000 kg/m³
h is the depth of sea level
P = ρ g h
P = 1000 x 10 x 10
P = 100000 Pa
P = 100 kPa
Hence, the correct answer is option A
Answer:
1832
Explanation:
From;
Δp Δx = h/4π
Δp = uncertainty in momentum
Δx = uncertainty in position
h= Plank's constant
But p =mv hence, Δp= Δmv
m= mass, v= velocity
mass of electron = 9.11 * 10^-31 Kg
Mass of proton = 1.67 * 10^-27 Kg
since m is a constant,
Δv = h/Δxm4π
For proton;
Δv = 6.6 * 10^-34/4 * 3.14 * 1.67 * 10^-27 * 1 * 10^-10
Δv = 315 ms-1
For electron;
Δv = 6.6 * 10^-34/4 * 3.14 * 9.11 * 10^-31 * 1 * 10^-10
Δv = 577000 ms-1
Ratio of uncertainty of electron to that of proton = 577000 ms-1/315 ms-1= 1832