Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:
So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
Answer:
11/15
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Step-by-step explanation:
927 because step by step is that everyone is because you
Answer: 0.75
Step-by-step explanation:
We can do this by drawing a terminal side in a standard position and then drawing the associated triangle. We then use the Pythagoras theorem to find the missing side the hypotenuse. Then, this will give a Pythagorean Triplet of 3, 4 and 5.
We now have a triangle with the values of:
x = 4
y =3
h^2= 4^2 + 3^2
h^2 = 16 + 9
h^2 = 25
h = 5
h = 5
Tangent = opposite/adjacent
= y/x
= 3/4
= 0.75