Answer:
Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products
(b)Total enthalpies of reactants and products
ΔᵣH° is negative, so the reaction is exothermic.
Answer:
Oxygen is limiting reactant
Explanation:
Based on the chemical reaction:
2C2H6 + 7O2 → 6H2O + 4CO2
<em>2 mole of ethane reacts with 7 moles of oxygen</em>
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For a complete reaction of 5.25 moles of ethane are required:
5.25 moles Ethane * (7mol Oxygen / 2mol Ethane) = 18.38 moles of oxygen
As there are just 15.0 moles of oxygen
<h3>Oxygen is limiting reactant</h3>
Answer:
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Answer:
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Explanation:
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