If there are fractions, eliminate them using the right methods. Then gather x and y terms on one side, and the rest on the other side. Simplify.
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where represents the number of objects/people in the set and represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Nah fam math hard math can solve its own problems 82773919
I believe the correct answer from the choices listed above is option A. The <span>system can be changed so that the two equations have equal x-coefficients by multiplying </span><span>both sides of the top equation by 2 resulting to 6x + 4y = 24. Hope this answers the question.</span>
Hi!
A is the answer:⏬⏬⏬⏬⏬⏬⏬⏬
The distance around a triangle, better noun as de "perimeter of a triangle"
is the total distance around the outside, which can be found by adding together the length of each side.
Perimeter (P) = Length A + Length B + Lenght C
In this case, we know that each side measure 2 \frac{1}{8}81 feet, 3 \frac{1}{2}21 feet, and 2 \frac{1}{2}21feet but we have to rewrite each one of this mixed fractions as improper fractions:
2 \frac{1}{8}81 = \frac{16 + 1}{8}816+1 = \frac{17}{8}817
3 \frac{1}{2}21 = \frac{6 + 1}{2}26+1 = \frac{7}{2}27
2 \frac{1}{2}21 = \frac{4 + 1}{2}24+1 = \frac{5}{2}25
Then we just add all of them to find the perimeter:
 = \frac{17 + 28 + 20}{8}817+28+20 = \frac{65}{8}865
A: The distance around a triangle is \frac{65}{8}865feet