1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).
2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.
4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.
5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)
Hope this helped :) Have a great day
This is an obtuse angle.
Obtuse is big and a show-off, acute is cute and shy and small. right angle is striaght angle up and right-down...
Answer:
rent payment
Step-by-step explanation:
rent payment will always be the same because it is something that will stay the same.
groceries are different every month.
gas changes due to prices and places you go.
home repairs arent an every month cost.
A(1,3,5, 7,9}, B {0,1,2,3,4,5,6, 7,8,9} be the universal set and let A (0,2,4,6,8}, and C {2,3,5,7}. List the elements of the fo
kodGreya [7K]
Answer:
a) 
b) 
c) 
Step-by-step explanation:
We have the following universal set
We also have these following sets:
a) 
is the set of elements that belong to both A and B.
B is the universal set, so:
b) 
is the set with all elements that belong to C and do not belong to B.
B is the universal set, so:
c) 
Because of parenthesis, 
takes precedence.
In a), I explained the 
operation.
B is the universal set, so:
Now we have 
is the set formed by the elements that belong to at least one of A or C.
So:
