The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope
slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5
pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2
y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
Answer:
Your answer is 4x.
Step-by-step explanation:
Add 2+2
Combine your x's (like terms)
then you got 4 from 2+2
Add the leftover x so it makes 4+x then add it will give you 4x.
Answer:
Step-by-step explanation:
Family.
<h2>
Answer: Lines b & c are parallel.⇄</h2>
Step-by-step explanation:
- When lines are perpendicular, the product of their slope is -1 (the slopes are negative reciprocal).
- When lines are parallel, they have the same slope.
Slope = ( y₂ - y₁) / (x₂ - x₁)
Slope of Line b = ( 6 - 1 ) ÷ ( 1 - 9 )
= 5 ÷ (- 8)
= - ⁵/₈
Slope of Line c = ( 12 - 7 ) ÷ ( 2 - 10 )
= - ⁵/₈
⇒ Line b ║ Line c
If the graph crosses the x-axis and appears almost linear at the intercept, it is a single zero. If the graph touches the x-axis and bounces off of the axis, it is a zero with even multiplicity. If the graph crosses the x-axis at a zero, it is a zero with odd multiplicity. The sum of the multiplicities is the degree
