There is one critical point at (2, 4), but this point happens to fall on one of the boundaries of the region. We'll get to that point in a moment.
Along the boundary 
, we have
which attains a maximum value of
Along 
, we have
which attains a maximum of
Along 
, we have
which attains a maximum of
So over the given region, the absolute maximum of 
is 1578 at (2, 44).
Answer:
Use the distance formula to determine the distance between the two points.
Distance
=
√(x2−x1)^2 + (y2−y1)^2
Substitute the actual values of the points into the distance formula.
√ ( (−6) − 0)^2 +( (−3) − 4)^2
Subtract 0 from −6
√(−6)^2 + ( ( −3 ) −4 )^2
Raise −6 to the power of 2
√36 + ( ( −3 ) −4 )^2
Subtract 4 from −3
√36 + ( −7 )^2
Raise −7 to the power of 2
√ 36 + 49
Add 36 and 49
√85
I think it’s 12, if you take $360 and subtract the $120 deposit you get 240 and i divided that by 20 to get 12.
Answer:
Typically you have to turn in your projects and assessments to get an A depending your school policies
Step-by-step explanation:
