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2 years ago

Solve e / e = mc2 and m =3 and c = 3

Mathematics

1 answer:

faust18 [17]2 years ago

8 0

$\text{e = mc}^2$

$\text{Given that m = 3 and c = 3,}$

$e = (3)(3)^2 = 27$

Answer: e = 27

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Let's replace $x$ with $(9a)$ and $y$ with $(-10b)$ in the expansion:

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Let's simplify a bit:

$=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6$

$=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

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