5(0.85)t < 1.5 is 15% decay
50(1.05)t < 100 is 5% growth
150(1.50)t > 500 is 50% growth
50(1.15)t < 150 is 15% growth
256.5/18= 14.25
(14.25x2)+(18x2)= 64.5m
Answer:
- $8000 at 1%
- $2000 at 10%
Step-by-step explanation:
It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.
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<h3>setup</h3>
Let x represent the amount invested at 10%. Then 10000-x is the amount invested at 1%. The total interest earned is ...
0.10x +0.01(10000 -x) = 280
<h3>solution</h3>
Simplifying gives ...
0.09x +100 = 280
0.09x = 180 . . . . . . . subtract 100
x = 2000 . . . . . . divide by 0.09
10000 -x = 8000 . . . . amount invested at 1%
<h3>1.</h3>
$8000 should be invested in the 1% account
<h3>2.</h3>
$2000 should be invested in the 10% account
It is B because for every point going down, there is 3 to the left and so it is 1/3 and it has to be negative because its going left
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(Hope this helps you)
