2 + 2 x 4 - 16 = -6
How?
Use PEMDAS.
The first step that shows up is multiplication.
2 + 8 - 16
Next comes Addition.
10 - 16
-6
(a²-6)(a²-4) simplify
a⁴-4a²-6a²+24
Combine like terms
a⁴-10a²+24
Answer:
(√2)/2
Step-by-step explanation:
The ratio of the radius of the circle to the side of the inscribed square is the same regardless of the size of the objects.
The radius of the circle is half the length of the diagonal of the square. For simplicity, we can call the side of the square 1, so its diagonal is √(1²+1²) = √2 by the Pythagorean theorem. The radius is half that value, so is (√2)/2. The desired ratio is this value divided by 1.
Scaling up our unit square to one with a side length of 3 inches, we have ...
radius/side = ((3√2)/2) / 3 = (√2)/2
_____
A square with a side length of 3 inches will have an area of (3 in)² = 9 in².
Answer:
197,8879 N.
Step-by-step explanation:
The magnitude of the horizontal force exerted on the statue can be calculated using trigonometric functions.
The question given says that <em><u>Nancy</u></em> is <em><u>pushing</u></em> the statue with a force of<em><u> 120 N at a 60° angle to the horizontal</u></em> and <em><u>Harry</u></em> is <em><u>pulling</u></em> the statue with a force of <u><em>180 N at a 40° angle with the horizontal</em></u>.
With that information can be calculated the horizontal force exerted on the statue by Nancy, the horizontal force exerted on the statue by Harry and, adding that results, the total horizontal magnitude can be calculated.
The cosine function can be used to calculate the horizontal component of the forces exerted by Nancy and Harry, to determine the horizontal component of the force exerted on the statue.
F= (120 N cos 60°) + (180 N x cos 40°)
F= 197,8879 N