The initial temperature of the metal = 35 °C
<h3>Further explanation</h3>Heat can be formulated :
Q = m . c . ΔT
Q = heat, J
c = specific heat, J/g C
ΔT = temperature, °C
m = 20 g
c = 5 J/(g°C)
Q = 500 J
T₁ = 40 C
the initial temperature :
Formula Silver(II) Oxide
1 answer:
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Answer:
See explanation below
Explanation:
You are missing the structure, therefore, I will do an example with one that I found on another place to try to explain.
This acid mechanism always involves carbocations, and positive charges, never negative because we are in acidic mediums.
In the first step, the lone pairs of the oxigen from the epoxide, substract one hydrogen of the reactant.
Second step, the lone pairs of the oxygen from the reactant, do a nucleophylic attack to the carbon of the epoxide. In this case, it will do it to the most substitued carbon.
Then, in the third step by acid base equilibrium, the hydrogen from the reactant that attacked, is substracted from the molecule by a molecule of water (We are in acid medium, therefore, there is traces of water) and the final structure is formed.
Check picture for mechanism:
