Complete Question
A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane
The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?
Answer:
The mass of caffeine extracted is
Explanation:
From the question above we are told that
The K value is
The mass of the caffeine is
The volume of water is
The volume of caffeine is
The number of times the extraction was done is n = 3
Generally the mass of caffeine that will be extracted is
substituting values
Oxidation of D -Ribose in presence of hypobromous acid gives D-Ribonic acid
Answer:
hydrogen nitrate + sodium hydrochlorate- sodium nitrate+ water + co2 (acid base reaction)
silver nitrate + calcium chloride - silver chloride+ calcium nitrate ( double displacement reaction)
hydrogen + nitrogen - ammonia gas ( simple contact reaction)
hydrogen peroxide - water + oxygen ( single displacement reaction)
Hope it helps :)
Answer:
A.) 1
Explanation:
Propane only exists in one conformation. It does not have enough carbons to form branches, and there are only hydrogens attached to each carbon. Furthermore, there is no way to twist the carbon or change its orientation (ex. cis- and trans-) to result in a different structure of propane. There is no other way to represent the molecule without drawing a different molecule.