We are given
arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103
so, first term is 124
u(1)= 124
now, we can find common difference
now, we can find kth term
now, we can plug values
and we get
u(k) must be negative
so,
now, we can solve for k
so, it's closest integer value is
..............Answer
Answer:
15
Step-by-step explanation:
jdjeishebvejeisik2behe
Answer:
B. 33.5
Step-by-step explanation:
V=πr2h
3=π·2^2·8/3≈33.51032
Answer: x=-2
Step-by-step explanation:
First subtract 4 from both sides
Sqrt(x+3)=1
Then square both sides
X+3=1
Then subtract 3
X=-2
Hope this helps!
Answer:
1) A 1 1/3 2) C 1 5/12
Step-by-step explanation:
1) 2/6+4/8+5/10
Reduce 4/8 with 4 and 5/10 with 5.
2/6+1/2+1/2
Reduce 2/6 with 2.
1/3+1/2+1/2
Add fractions with a common denominator.
1/3+2/2
Reduce 2/2 with 1
1/3+1
Write all numerators above the common denominator.
1+3/3
Calculate.
4/3 = 1 1/3
2) 2 3/4 - 1 1/3
Change to improper fractions.
11/4 - 4/3
Write all numerators above the common denominator.
33-16/12
Calculate.
17/12 = 1 5/12
Hope this helps :)
