Answer:
angle 3- 131
angle 2- 112
angle 5- 37
angle 1- 80
angle 4- 80
hope this helps :)- please crown me brainliest!!!
Answer:
No DB is not a perpendicular bisector of AC
Step-by-step explanation:
This is because as AC is a straight line it's angle degree is 180 which when bisected by DB becomes,
180 ÷ 2 = 90
On both the angles i.e <BDC = <NDA = 90°
To make it a perpendicular bisector but
<BDC is not equal to <NDA is not equal to 90°.
Hence, DB is not a perpendicular bisector of line AC.
Answer:
Step-by-step explanation:
(A) The given statement is:A square is a parallelogram-------A square is always a parallelogram (By properties of parallelogram)(B) The given statement is:A rectangle is a trapezoid----------A rectangle is never a trapezoid.(C) The given statement is:A rhombus is a square--------A rhombus is sometimes a square.(D) The given statement is:A quadrilateral is a kite--------A quadrilateral is sometimes a kite.
The normal body temperature : to = 37° C
An inequality is:
| t - to | ≤ 3
| t - 37 | ≤ 3
t - 37 ≤ 3 AND ( - t - 37 ) ≤ 3
t ≤ 3 +
37
- t + 37 ≤ 3
t ≤
40
- t ≤ 3 - 37
- t ≤ - 34 / *( - 1 )
t ≥ 34
Answer t <span>∈ [</span><span>
34</span><span>°C,</span><span>
40</span><span>° C ]</span>.
When x = 8 y = 15
The way to figure this out is to subtract 12 by 5. That’s 7 so there’s a difference of 7 between both of the numbers.
Hope this helped!
